CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    The focus of the parabola\[{{y}^{2}}-x-2y+2=0\]is:

    A)  \[\left( \frac{1}{4},0 \right)\]                    

    B)  \[(1,2)\]

    C)  \[\left( \frac{5}{4},1 \right)\]    

    D)         \[\left( \frac{3}{4},1 \right)\]

    E)  \[\left( \frac{3}{4},2 \right)\]

    Correct Answer: C

    Solution :

    The equation of parabola can be rewritten as \[{{y}^{2}}-2y+1=x-1\] \[\Rightarrow \]               \[{{(y-1)}^{2}}=(x-1)\] Let \[Y=y-1\]and\[X=x-1\] \[\therefore \]Equation of parabola becomes\[{{Y}^{2}}=X\] Here,      \[a=\frac{1}{4}\] \[\therefore \] Focus for the parabola\[{{Y}^{2}}=X\]is\[\left( \frac{1}{4},0 \right)\]. \[\therefore \] Focus for parabola\[{{(y-1)}^{2}}=(x-1)\]is\[\left( \frac{5}{4},1 \right)\]


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