A) \[{{x}^{2}}+{{y}^{2}}-x-y=0\]
B) \[{{x}^{2}}+{{y}^{2}}+x+y=0\]
C) \[{{x}^{2}}+{{y}^{2}}+2(x-y)=0\]
D) \[{{x}^{2}}+{{y}^{2}}-2x+y=0\]
E) \[{{x}^{2}}+{{y}^{2}}+2x-y=0\]
Correct Answer: A
Solution :
The co-ordinate of the point of intersection of line y = x and circle\[{{x}^{2}}+{{y}^{2}}-2x=0\]is\[A(0,0)\]and B (1,1). \[\therefore \]Equation of circle with AB as its diameter is \[x(x-1)+y(y-1)=0\] \[\Rightarrow \] \[{{x}^{2}}+{{y}^{2}}-x-y=0\]
You need to login to perform this action.
You will be redirected in
3 sec
