A) \[x-y-z-15=0\]
B) \[x-y+z-15=0\]
C) \[x+y+z-15=0\]
D) \[x+\text{ }y+\text{ }z+15=0\]
E) \[x-y-z+\text{ }15=0\]
Correct Answer: C
Solution :
\[\because \]Midpoint of line joining (2, 3,4) and (6, 7,8) is (4, 5, 6) this point is satisfied by one equation \[x+y+z-15=0\] \[\therefore \]\[x+y+z-15=0\]is required equation of plane.
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