A) \[b=2h\]
B) \[b=3h\]
C) \[b=(1+\sqrt{3})h\]
D) \[b=(2+\sqrt{3})h\]
E) \[2b=3h\]
Correct Answer: A
Solution :
In \[\Delta POR,\] \[\frac{PR}{\sin 90{}^\circ }=\frac{h}{\sin 67{{\frac{1}{2}}^{o}}}\] ?.(i) and in\[\Delta PQR,\] \[\frac{PR}{\sin 22{{\frac{1}{2}}^{o}}}=\frac{b}{\sin 45{}^\circ }\] ?.(ii) From Eqs. (i) and (ii) \[\frac{h}{b}=\frac{\sqrt{2}}{2}(\cos 45{}^\circ -\cos 90{}^\circ )\] \[=\frac{1}{2}\] \[\Rightarrow \] \[2h=b\]You need to login to perform this action.
You will be redirected in
3 sec