A) 100 N
B) 110 N
C) 209 N
D) 206 N
E) 196 N
Correct Answer: E
Solution :
Force applied against friction \[{{f}_{k}}={{\mu }_{k}}R={{u}_{k}}mg=\frac{1}{3}\times 60\times 9.8\] \[=196\,N\]You need to login to perform this action.
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