A) \[4\text{ }m{{s}^{-1}}\]
B) \[\text{6 }m{{s}^{-1}}\]
C) \[\text{10 }m{{s}^{-1}}\]
D) \[\text{12 }m{{s}^{-1}}\]
E) \[\text{14 }m{{s}^{-1}}\]
Correct Answer: B
Solution :
\[{{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}=({{m}_{1}}+{{m}_{2}})v\] \[\Rightarrow \]\[10\times {{u}_{1}}+5\times 0=(10+5)\times 4\] \[\Rightarrow \]\[{{u}_{1}}=\frac{15\times 4}{10}=6\,m{{s}^{-1}}\]
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