CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    An athlete throws a discus from rest to a final angular velocity of 15 rad/s in 0.270 s before releasing it. During acceleration, discus moves a circular arc of radius 0.810 m. Acceleration of discus before it is released is...... \[m{{s}^{-2}}\].

    A)  45  

    B)         182

    C)  187                       

    D)         192

    E)  205

    Correct Answer: A

    Solution :

          \[\omega ={{\omega }_{0}}+\alpha t\] \[\Rightarrow \]               \[\omega =0+\alpha t\] \[\Rightarrow \]               \[\alpha =\frac{15}{0.270}rad/{{s}^{2}}\] Now, \[a=r,\alpha =0.81\times \frac{15}{0.270}=45\,m{{s}^{-2}}\]           


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