A) \[H\]
B) \[H{{e}^{+}}\]
C) \[{{B}^{4+}}\]
D) \[L{{i}^{2+}}\]
E) \[B{{e}^{2+}}\]
Correct Answer: B
Solution :
Out of other alternates.\[H{{e}^{+}}\]has ionization energy of 54.4 eV because in\[H{{e}^{+}}\]effective nuclear charge is fairly high and ionic size is small.
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