A) \[\frac{p}{32}\]
B) \[\left( \frac{24}{5} \right)p\]
C) \[8P\]
D) \[\text{32 }P\]
E) \[16\text{ }P\]
Correct Answer: D
Solution :
\[P{{V}^{\gamma }}=constant\] \[\Rightarrow \] \[\frac{{{p}_{2}}}{{{p}_{1}}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma }}\] \[\therefore \] \[\frac{{{p}_{2}}}{p}={{\left( \frac{800}{100} \right)}^{5/3}}\] \[\Rightarrow \] \[{{p}_{2}}=32p\]
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