CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    The enthalpy change for the transition of liquid water to steam is\[40.8\text{ }kJ\text{ }mo{{l}^{-1}}\]at 373 K. What is the entropy of vaporization of water?

    A)  209.4                   

    B)         109.4

    C)  \[-109.4\]          

    D)         \[-209.4\]

    E)  250.4

    Correct Answer: C

    Solution :

    \[{{\Delta }_{vap}}{{S}^{\varnothing }}=\frac{{{\Delta }_{vap}}{{H}^{\varnothing }}}{T}\] \[{{\Delta }_{vap}}{{S}^{\varnothing }}=\frac{40.8\times {{10}^{3}}}{373}=109.4\,J{{K}^{-1}}mo{{l}^{-1}}\]


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