A) 2.88
B) 3.6
C) 4.0
D) 1.0
E) 2.0
Correct Answer: A
Solution :
For\[0.1M\]acetic acid, or \[C=0.1\,J{{K}^{-1}}mo{{l}^{-1}}\] \[{{K}_{a}}=1.74\times {{10}^{-5}}\] \[pH=?\] According to Ostwald dilution formula, \[[{{H}^{+}}]=\sqrt{{{K}_{a}}\times C}\] \[=\sqrt{1.7\times {{10}^{-5}}\times 0.1}\] \[=\sqrt{0.017\times {{10}^{-4}}}\] \[pH=-{{\log }_{10}}[{{H}^{+}}]\] \[=-{{\log }_{10}}[\sqrt{0.017\times {{10}^{-4}}}]\] \[pH=2.88\]
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