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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    \[100\text{ }g\text{ }CaC{{O}_{3}}\]is treated with 1 L of \[1N\text{ }HCl\]. What would be the weight of\[C{{O}_{2}}\]liberated after the completion of the reaction?

    A) 55 g                                       

    B) 11 g

    C) 22 g                       

    D)        33 g

    E) 44 g

    Correct Answer: A

    Solution :

    \[CaC{{O}_{3}}\xrightarrow[{}]{{}}C{{O}_{2}}\]                 \[(20+12+48=80)\,(12+32=44)\] \[80\text{ }g\text{ }CaC{{O}_{3}}\]produces \[=44\text{ }g\text{ }C{{O}_{2}}\] \[100\text{ }g\,CaC{{O}_{3}}\]produces\[=\frac{44}{80}\times 100\] \[=55g\]


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