A) \[Ca{{C}_{2}}\]
B) \[SiC\]
C) \[M{{g}_{2}}{{C}_{3}}\]
D) \[A{{l}_{4}}{{C}_{3}}\]
E) \[B{{e}_{2}}C\]
Correct Answer: A
Solution :
\[Ca{{C}_{2}}+2{{H}_{2}}O\xrightarrow[{}]{{}}Ca{{(OH)}_{2}}+\underset{ethyne}{\mathop{HC\equiv CH}}\,\]
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