A) 0.018 amu
B) 0.18 amu
C) 0.0018 amu
D) 1.8 amu
E) 18 amu
Correct Answer: A
Solution :
Total mass of \[_{1}^{2}H+_{1}^{3}H\xrightarrow[{}]{{}}_{2}^{4}He+_{0}^{1}n\] In the above reaction, Total mass of LHS\[=2.014+3.016=5.030\] Total mass of RHS\[=5.012\] Mass loss while forming the products \[=5.030-5.012\] \[=0.018\,amu\]
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