CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    \[f(x)=\] \[\left| \begin{matrix}    1 & x & x+1  \\    2x & x(x-1) & (x+1)x  \\    3x(x-1) & x(x-1)(x-2) & (x+1)x(x-1)  \\ \end{matrix} \right|\] then\[f(100)\]is equal to:

    A)  0                            

    B)  1

    C)  100                       

    D)         \[-100\]

    E)  \[-1\]

    Correct Answer: A

    Solution :

                    \[\because \]\[f(x)=\] \[\left| \begin{matrix}    1 & x & x+1  \\    2x & x(x-1) & (x+1)x  \\    3x(x-1) & x(x-1)(x-2) & (x+1)x(x-1)  \\ \end{matrix} \right|\] Now, \[f(100)=\left| \begin{matrix}    1 & 100 & 101  \\    200 & 9900 & 10100  \\    29700 & 970200 & 999900  \\ \end{matrix} \right|\] \[=\left| \begin{matrix}    1 & 100 & 1  \\    200 & 9900 & 200  \\    29700 & 970200 & 29700  \\ \end{matrix} \right|{{C}_{3}}\to {{C}_{3}}-{{C}_{2}}\] \[=0\]


You need to login to perform this action.
You will be redirected in 3 sec spinner