CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    If\[x=(\beta -\gamma )(\alpha -\delta ),y=(\gamma -\alpha )(\beta -\delta ),\] \[z=(\alpha -\beta )(\gamma -\delta ),\]then   the   value   of\[{{x}^{3}}+{{y}^{3}}+{{z}^{3}}-3xyz\]is:

    A)  0                                            

    B) \[{{\alpha }^{6}}+{{\beta }^{6}}+{{\gamma }^{6}}+{{\delta }^{6}}\]

    C)  \[{{\alpha }^{6}}{{\beta }^{6}}{{\gamma }^{6}}{{\delta }^{6}}\]    

    D)         1

    E)  none of these

    Correct Answer: A

    Solution :

    \[\because \]\[x+y+z=(\beta -\gamma )(\alpha -\delta )+(\gamma -\alpha )(\beta -\delta )\] \[+(\alpha -\beta )(\gamma -\delta )\] \[=0\] \[\therefore \]\[~{{x}^{3}}+{{y}^{3}}+{{z}^{3}}-3xyz=(x+y+z)\] \[({{x}^{2}}+{{y}^{2}}+{{z}^{2}}-xy-yz-zx)\] \[=0\]


You need to login to perform this action.
You will be redirected in 3 sec spinner