A) \[1\]
B) \[0\]
C) \[-\sqrt{3}\]
D) \[\sqrt{3}\]
E) \[6\]
Correct Answer: B
Solution :
\[\because \]\[\overrightarrow{a},\overrightarrow{b}\]and\[\overrightarrow{c}\]are coplanar vectors, so \[2\overrightarrow{a}-\overrightarrow{b},2\overrightarrow{b}-\overrightarrow{c}\]and\[2\overrightarrow{c}-\overrightarrow{a}\]are also coplanar. \[\therefore \] \[[2\overrightarrow{a}-\overrightarrow{b}2\overrightarrow{b}-\overrightarrow{c}2\overrightarrow{c}-\overrightarrow{a}]=0\]
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