A) \[\frac{9}{25}\]
B) \[\frac{3}{5}\]
C) \[\frac{25}{5}\]
D) \[\frac{1}{25}\]
E) \[25\]
Correct Answer: A
Solution :
Distance covered in 5 s \[{{s}_{1}}=\frac{1}{2}a{{t}^{2}}\] \[=\frac{1}{2}a{{(5)}^{2}}\] \[=\frac{25a}{2}\] Distance covered in 5th second \[{{s}_{2}}=\frac{1}{2}\times a(2\times 5-1)\] \[=\frac{9}{2}a\] \[\frac{{{s}_{2}}}{{{s}_{1}}}=\frac{9}{25}\]
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