CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    If\[{{\log }_{0.3}}(x-1)<{{\log }_{0.09}}(x-1),\]then\[x\ne 1\]lies in:

    A)  (1, 2)                                    

    B)  \[(0,\text{ }1)\]

    C) \[(1,\infty )\]                    

    D)         \[(2,\infty )\]

    E)  \[(0.09,0.3)\]

    Correct Answer: D

    Solution :

    \[{{\log }_{0.3}}(x-1)<{{\log }_{0.09}}(x-1)\] \[\Rightarrow \]               \[{{\log }_{0.3}}(x-1)<{{\log }_{{{(0.3)}^{2}}}}(x-1)\] \[\Rightarrow \]               \[{{\log }_{0.3}}(x-1)<\frac{1}{2}{{\log }_{0.3}}(x-1)\] \[\Rightarrow \]               \[{{\log }_{0.3}}(x-1)<0\] \[\Rightarrow \]               \[(x-1)>1\Rightarrow x>2\]and \[x>1\] \[\therefore \]  \[x\in (2,\infty )\]


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