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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    A particle is displaced from a position\[(2\hat{i}-\hat{j}+\hat{k})\]to another position\[(3\hat{i}+2\hat{j}-2\hat{k})\] under the action of the force of\[(2\hat{i}+\hat{j}-\hat{k})\]. The work done by the force in an arbitrary unit is:

    A)  8                            

    B)         10

    C)  12                         

    D)         16

    E)  20

    Correct Answer: A

    Solution :

    Work done \[W=\overrightarrow{F}.\overrightarrow{r}\] \[=(2\hat{i}+\hat{j}-\hat{k}).[(3\hat{i}+2\hat{j}-2\hat{k})\]\[-(2\hat{i}-\hat{j}+\hat{k})]\] \[=(2\hat{i}+\hat{j}-\hat{k}).(\hat{i}+3\hat{j}-3\hat{k})\] \[=2+3+3\] \[=8\]unit


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