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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    An object is projected at an angle of\[45{}^\circ \]with the horizontal. The horizontal range and maximum height reached will be in the ratio:

    A)  \[1:2\]                                 

    B)  \[2:1\]

    C)  \[1:4\]                 

    D)         \[4:1\]

    E)  \[4:\sqrt{2}\]

    Correct Answer: D

    Solution :

    Horizontal range, \[R=\frac{{{u}^{2}}\sin 2\times 45}{g}\] \[=\frac{{{u}^{2}}}{g}\] Maximum height, \[h=\frac{{{u}^{2}}{{\sin }^{2}}45}{2g}\]                                 \[=\frac{{{u}^{2}}}{4g}\]                 \[\frac{R}{h}=\frac{4}{1}\]


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