A) \[\frac{M{{L}^{2}}}{6}\]
B) \[\frac{M{{L}^{2}}}{12}\]
C) \[\frac{7M{{L}^{2}}}{24}\]
D) \[\frac{7M{{L}^{2}}}{12}\]
E) \[\frac{7M{{L}^{2}}}{48}\]
Correct Answer: E
Solution :
\[{{I}_{CD}}={{I}_{CM}}+M{{\left( \frac{L}{4} \right)}^{2}}=\frac{M{{L}^{2}}}{12}+\frac{M{{L}^{2}}}{16}\] \[=\frac{7M{{L}^{2}}}{48}\]You need to login to perform this action.
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