CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    Three identical spheres, each of mass 1 kg are kept as shown in figure below, touching each other, with their centres on a straight line. If their centres are marked P, Q, R respectively, the distance of centre of mass of the system from P is:

    A)  \[\frac{PQ+PR+QR}{3}\]             

    B)  \[\frac{PQ+PR}{3}\]

    C)  \[\frac{PQ+QR}{3}\]     

    D)         \[\frac{PR+QR}{3}\]

    E)  \[\frac{PQ+QR+PR}{6}\]             

    Correct Answer: B

    Solution :

    \[{{r}_{1}}=0,{{r}_{2}}=PQ,{{r}_{3}}=PR\] Distance of centre of mass from P is \[r=\frac{{{r}_{1}}+{{r}_{2}}+{{r}_{3}}}{3}=\frac{0+PQ+PR}{3}=\frac{PQ+PR}{3}\]


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