CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    A body rolls down an inclined plane. If its kinetic energy of rotation is 40% of its kinetic energy of translation, then the body is:

    A)  solid cylinder   

    B)         solid sphere

    C)  disc                      

    D)         ring

    E)  hollow cylinder

    Correct Answer: B

    Solution :

    \[\frac{1}{2}I{{\omega }^{2}}=40%of\frac{1}{2}m{{v}^{2}}\] \[\frac{1}{2}I{{\omega }^{2}}=\frac{40}{100}\left( \frac{1}{2}m{{r}^{2}}{{\omega }^{2}} \right)\] \[I=\frac{2}{5}m{{r}^{2}}\] So, the body is solid sphere.


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