CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    A manometer connected to a closed tap reads\[4.5\times {{10}^{5}}Pa\]. When the tap is opened the reading of the manometer falls to\[4\times {{10}^{5}}Pa\]. Then the velocity of flow of water is:

    A) \[7\text{ }m{{s}^{-1}}\]                

    B)         \[8\text{ }m{{s}^{-1}}\]

    C)  \[9m{{s}^{-1}}\]              

    D)         \[12m{{s}^{-1}}\]

    E)  \[10\text{ }m{{s}^{-1}}\]

    Correct Answer: E

    Solution :

    \[\frac{1}{2}\rho {{v}^{2}}=({{p}_{1}}-{{p}_{2}})\] \[\frac{1}{2}\times {{10}^{3}}\times {{v}^{2}}=(4.5\times {{10}^{5}}-4\times {{10}^{5}})\]                 \[{{v}^{2}}=0.5\times {{10}^{2}}\times 2\]                 \[=100\] \[\Rightarrow \]               \[v=10\,m/s\]


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