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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    A set of 24 tuning forks are so arranged that each gives 6 beats/s with the previous one. If the frequency of the last tuning fork is double that of the first, frequency of the second tuning fork is:

    A)  138 Hz                 

    B)         132 Hz

    C)  144 Hz                 

    D)         276 Hz

    E)  270 Hz

    Correct Answer: C

    Solution :

    The frequencies of tuning forks are the terms of an AP whose common difference is 6. \[\therefore \]  \[l=a+(n-1)d\]                 \[2a=a+(24-1)\times 6\]                 \[a=23\times 6\]                 \[=138\] \[\therefore \]Second frequency\[=138+6\]         \[=144\text{ }Hz\]


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