question_answer

A parallel plate capacitor of capacitance\[10\mu F\]is charged to\[1\mu C\]. The charging battery is removed and then the separation between the plates is doubled. Work done during the process is:

A)  \[5\text{ }m\text{ }J\]                 

B)         \[0.05\text{ }m\text{ }J\]

C)  \[\text{1 }m\text{ }J\]                 

D)         \[10\text{ }m\text{ }J\]

E)  \[\text{50 }m\text{ }J\]