A) 0.08
B) 0.8
C) 8
D) 80
E) \[\frac{1}{8}\]
Correct Answer: C
Solution :
\[\underset{\begin{smallmatrix} \,\,\,\,\,1 \\ (1-x) \end{smallmatrix}}{\mathop{A(g)}}\,+\underset{\begin{smallmatrix} \,\,\,\,\,1 \\ (1-3x) \end{smallmatrix}}{\mathop{3B(g)}}\,\underset{\begin{smallmatrix} 0 \\ 4x \end{smallmatrix}}{\mathop{4C(g)}}\,\underset{\begin{smallmatrix} (initial\text{ }concentration) \\ (final\text{ }concentration) \end{smallmatrix}}{\mathop{{}}}\,\] (at equilibrium) According to question,\[1-x=4x\] \[\therefore \] \[x=\frac{1}{5}\] For above reaction \[{{K}_{c}}=\frac{{{[C]}^{4}}}{[A]{{[B]}^{3}}}=\frac{{{(4x)}^{4}}}{(1-x){{(1-3x)}^{3}}}\] \[{{K}_{c}}=\frac{{{\left( 4\times \frac{1}{5} \right)}^{4}}}{\left( 1-\frac{1}{5} \right){{\left( 1-3\times \frac{1}{5} \right)}^{3}}}=8.0\]
You need to login to perform this action.
You will be redirected in
3 sec
