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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    The vant Hoff factor of\[BaC{{l}_{2}}\]at 0.01 M concentration is 1.98. The percentage of dissociation of\[BaC{{l}_{2}}\]at this concentration is:

    A) 49                          

    B)        69

    C) 89                          

    D)        98

    E) 100

    Correct Answer: A

    Solution :

                             \[BaC{{l}_{2}}B{{a}^{2+}}+2C{{l}^{-}}\] Initial                  0.01M At equilibrium    \[(0.01-x)MxM2xM\]                 \[i=\frac{(0.01-x)+x+2x}{0.01}\]                 \[=\frac{0.01+2x}{0.01}=1.98\]                 \[x=0.0049\] \[%\,a=\frac{x}{0.01}\times 100=\frac{0.0049\times 100}{0.01}=49%\]


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