A) \[1:2\]
B) \[1:1\]
C) \[1:\sqrt{2}\]
D) \[4:1\]
E) \[\sqrt{2}:1\]
Correct Answer: A
Solution :
de-Broglie wavelength, =\[\lambda =\frac{h}{\sqrt{2m{{E}_{k}}}}\] \[\frac{{{\lambda }_{\alpha }}}{{{\lambda }_{p}}}=\sqrt{\frac{{{m}_{p}}}{{{m}_{\alpha }}}}\] \[=\sqrt{\frac{1}{4}}=\frac{1}{2}\]
You need to login to perform this action.
You will be redirected in
3 sec
