A) 0
B) 1
C) 2
D) 3
E) 4
Correct Answer: D
Solution :
The structure of butane-2, 3-diol is as: \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{{{C}^{*}}}}}\,-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{{{C}^{*}}}}}\,-C{{H}_{3}}\] \[\because \]Optical isomers in compounds have similar asymmetric carbon atom, which are even in number \[={{2}^{n}}-1\] Here, \[n=2\] \[\therefore \]total number of optically active stereoisomers \[={{2}^{2}}-1=3\]
You need to login to perform this action.
You will be redirected in
3 sec
