A) \[1.8\times {{10}^{15}}\]
B) \[8.5\times {{10}^{15}}\]
C) \[1.8\times {{10}^{10}}\]
D) \[85\times {{10}^{15}}\]
Correct Answer: B
Solution :
\[E_{cell}^{o}=\frac{0.059}{2}\log {{K}_{c}}\] \[\log {{K}_{c}}=\frac{E_{cell}^{o}\times 2}{0.059}\] \[\log {{K}_{c}}=\frac{0.47\times 2}{0.059}\] \[{{K}_{c}}=8.5\times {{10}^{15}}\]
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