A) 1
B) 2
C) 3
D) 4
E) 5
Correct Answer: E
Solution :
\[{{\log }_{2}}{{\log }_{2}}{{\log }_{4}}256+2{{\log }_{\sqrt{2}}}2\] \[=lo{{g}_{2}}\text{ }lo{{g}_{2}}\text{ }lo{{g}_{4}}{{(4)}^{4}}+2\frac{1}{{{\log }_{2}}\sqrt{2}}\] \[={{\log }_{2}}{{\log }_{2}}4+\frac{4}{{{\log }_{2}}2}\] \[={{\log }_{2}}2+4=1+4=5\]You need to login to perform this action.
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