CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    A vector perpendicular to\[2\hat{i}+\hat{j}+\hat{k}\]and coplanar with\[\hat{i}+2\hat{j}+\hat{k}\] and\[\hat{i}+\hat{j}+2\hat{k}\]is:

    A)  \[5(\hat{j}-\hat{k})\]                    

    B)         \[\hat{i}+7\hat{j}-\hat{k}\]

    C)  \[5(\hat{j}+\hat{k})\]                   

    D)         \[2\hat{i}-7\hat{j}-\hat{k}\]

    E)  \[5(\hat{i}+\hat{k})\]

    Correct Answer: A

    Solution :

    Any vector\[\bot \]to\[\overrightarrow{a}\]and coplanar to\[\overrightarrow{b}\]and\[\overrightarrow{c}\]is given by\[\overrightarrow{a}\times (\overrightarrow{b}\times \overrightarrow{c})\] \[\therefore \]Required vector is \[(2\hat{i}+\hat{j}+\hat{k})\times [(\hat{i}+2\hat{j}+\hat{k})\times (\hat{i}+\hat{j}+2\hat{k})]\] \[=(2\hat{i}+\hat{j}+\hat{k})\times \left| \begin{matrix}    {\hat{i}} & {\hat{j}} & {\hat{k}}  \\    1 & 2 & 1  \\    1 & 1 & 2  \\ \end{matrix} \right|\] \[=(2\hat{i}+\hat{j}+\hat{k})\times (3\hat{i}-\hat{j}-\hat{k})\] \[=\left| \begin{matrix}    {\hat{i}} & {\hat{j}} & {\hat{k}}  \\    2 & 1 & 1  \\    3 & -1 & -1  \\ \end{matrix} \right|=5(\hat{j}-\hat{k})\]


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