A) 1.66 Wb
B) 1.66 nWb
C) 1.66 mWb
D) \[1.66\mu Wb\]
E) 1.66 pWb
Correct Answer: C
Solution :
\[\phi ={{\mu }_{r}}{{\mu }_{0}}\frac{{{N}^{2}}}{l}Ai\] \[=600\times 4\pi \times {{10}^{-7}}\times 50\times 50\pi \] \[\times \frac{\,\,\,\,\,\,\,\,\,\,\,\,\times {{(7.5\times {{10}^{-3}})}^{2}}\times 3}{6\times {{10}^{-1}}}\] \[=1.66\times {{10}^{-3}}Wb=1.66\text{ }mWb.\]You need to login to perform this action.
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