CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    \[\int_{0}^{2}{[{{x}^{2}}]}dx\]is:

    A)  \[2-\sqrt{2}\]                                   

    B)  \[2+\sqrt{2}\]

    C)  \[\sqrt{2}-1\]                   

    D)         \[-\sqrt{2}-\sqrt{3}+5\]

    E)  none of these

    Correct Answer: D

    Solution :

    \[\int_{0}^{2}{[{{x}^{2}}]}\,dx\] \[=\int_{0}^{1}{[{{x}^{2}}]}\,dx+\int_{1}^{\sqrt{2}}{[{{x}^{2}}]}dx+\int_{\sqrt{2}}^{\sqrt{3}}{[{{x}^{2}}]}\,dx\]                                                 \[=\int_{\sqrt{3}}^{2}{[{{x}^{2}}]}\,dx\] \[=\int_{0}^{1}{0\,}dx+\int_{1}^{\sqrt{2}}{1\,}dx+\int_{\sqrt{2}}^{\sqrt{3}}{2\,dx}+\int_{\sqrt{3}}^{2}{3\,}dx\] \[=[x]_{1}^{\sqrt{2}}+[2x]_{\sqrt{2}}^{\sqrt{3}}+[3x]_{\sqrt{3}}^{2}\] \[=\sqrt{2}-1+2\sqrt{3}-2\sqrt{2}+6-3\sqrt{3}\] \[=5-\sqrt{3}-\sqrt{2}\]


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