CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    At a temperature of\[30{}^\circ C,\]the susceptibility of a ferromagnetic material is found to be\[\chi \]. Its susceptibility at\[333{}^\circ C\]is:

    A)  \[\chi \]                              

    B)         \[0.5\chi \]

    C)  \[2\chi \]                            

    D)         \[11.1\chi \]

    E)  \[0.09\chi \]

    Correct Answer: E

    Solution :

    Susceptibility of ferromagnetic material is inversely proportional to temperature \[\chi \propto \frac{1}{T}\] \[\therefore \]  \[\frac{{{\chi }_{1}}}{{{\chi }_{2}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\] Given \[T=30{}^\circ C,{{T}_{2}}=333{}^\circ C,{{\chi }_{1}}=\chi \] \[\therefore \]  \[{{\chi }_{2}}=\frac{{{T}_{1}}}{{{T}_{2}}}\chi =\frac{30}{333}\chi =0.09\chi \]


You need to login to perform this action.
You will be redirected in 3 sec spinner