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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    In an arithmetic progression, the 24 th term is 100. Then the sum of the first 47 terms of the arithmetic progression is:

    A)  2300                     

    B)         2350

    C)  2400                     

    D)         4600

    E)  4700

    Correct Answer: E

    Solution :

    Let a and b be the first term and common difference of an AP. According to the given condition, \[a+23d=100\]                 ...(i) And \[{{S}_{47}}=\frac{47}{2}[2a+46d]=47[a+23d]\] \[=47\times 100=4700\]                   (from (i))


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