CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    The standard deviation of n observations \[{{x}_{1}},{{x}_{2}},.....,{{x}_{n}}\]is 2. If\[\sum\limits_{i=1}^{n}{{{x}_{i}}}=20\]and\[\sum\limits_{i=1}^{n}{x_{i}^{2}}=100,\]then n is:

    A)  10 or 20              

    B)         5 or 10

    C)  5 or 20                 

    D)         5 or 15

    E)  25

    Correct Answer: C

    Solution :

    We know \[SD=\sqrt{\frac{\sum{x_{i}^{2}}}{n}-{{\left( \frac{\sum{{{x}_{i}}}}{n} \right)}^{2}}}\] \[\therefore \]\[2=\sqrt{\frac{100}{n}-{{\left( \frac{20}{n} \right)}^{2}}}=\sqrt{\frac{100}{n}-\frac{400}{{{n}^{2}}}}\] \[\Rightarrow \]\[4=\frac{100}{n}-\frac{400}{{{n}^{2}}}\] \[\Rightarrow \]\[{{n}^{2}}-25n+100=0\]\[\Rightarrow \]\[n=20,5\]


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