A) 455
B) 1575
C) 1120
D) 2030
E) 1930
Correct Answer: D
Solution :
Number are either all even or one even and other two odd. \[\therefore \]Required number of ways \[{{=}^{15}}{{C}_{3}}{{+}^{15}}{{C}_{1}}{{\times }^{15}}{{C}_{2}}\] \[=\frac{15!}{3!\times 12!}+\frac{15!}{14!}\times \frac{15!}{2!\times 13!}\] \[=\frac{15\times 14\times 13}{6}+\frac{15\times 15\times 14}{2}\] \[=455+1575=2030\]
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