The ratio of charges flowing through the wire at different times is:
A) \[2:1:2\]
B) \[1:3:3\]
C) \[1:1:1\]
D) \[2:3:4\]
E) \[2:3:3\]
Correct Answer: C
Solution :
Since, charge (q) = current (i) \[\times \] time (t) therefore charge is equal to area under the curve. \[\therefore \]Ist rectangle \[=q=lb=2\] IInd rectangle \[=q=lb=2\] IIIrd triangle\[=q=\frac{1}{2}lb=2\] Hence, ratio is\[1:1:1.\]
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