CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    In a gas, two waves of wavelengths 1 m and 1.01 m are superposed and produce 10 beats in s. The velocity of sound in the medium is:

    A)  300 m/s              

    B)         336.7 m/s

    C)  360.2 m/s     

    D)         270 m/s

    E)  390 m/s

    Correct Answer: B

    Solution :

    The velocity (v) is given by \[v=f\lambda \] \[\Rightarrow \]               \[f=\frac{v}{\lambda }\] Number of beats = difference in frequencies \[\therefore \]  \[{{f}_{1}}-{{f}_{2}}=v\left( \frac{1}{{{\lambda }_{1}}}-\frac{1}{{{\lambda }_{2}}} \right)\]                 \[\frac{10}{3}=v\left( \frac{1}{1}-\frac{1}{1.01} \right)\]                 \[\frac{10}{3}=v\left( \frac{0.01}{1.01} \right)\] \[\Rightarrow \]               \[v=\frac{10\times 1.01}{3\times 0.01}=336.7\,m/s\]


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