A) \[2\times {{10}^{2}}T\]
B) \[6\times {{10}^{7}}T\]
C) \[6\times {{10}^{2}}T\]
D) \[2\times {{10}^{-7}}T\]
E) \[3\times {{10}^{8}}T\]
Correct Answer: D
Solution :
The instantaneous magnitudes of electric field (E) and magnetic field (B) are related as \[\frac{E}{B}=c\] \[\Rightarrow \] \[B=\frac{E}{c}\] Given, \[E=60\,V/m,c=3\times {{10}^{8}}m/s\]. \[\therefore \] \[B=\frac{60}{3\times {{10}^{8}}}=2\times {{10}^{-7}}T\]
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