A) Diaminedichloroplatinum (II)
B) Tetraaminedichlorocobalt (III) chloride
C) Potassium hexacyanoferrate (II)
D) Hexaaquochromium (III) bromide
E) Pentacarbonyl iron (0)
Correct Answer: C
Solution :
The molar conductivity of potassium hexacyanoferrate (II) i.e.,\[{{K}_{4}}[Fe{{(CN)}_{6}}]\]is highest because it gives maximum number of ions on ionisation. \[{{K}_{4}}[Fe{{(CN)}_{6}}]\xrightarrow[{}]{{}}4{{K}^{+}}+{{[Fe{{(CN)}_{6}}]}^{4-}}\]
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