CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    The enol form of acetone after treatment with\[{{D}_{2}}O,\]gives:

    A) \[{{H}_{3}}C-\underset{\begin{smallmatrix}  | \\  OD \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}\]

    B) \[{{H}_{3}}C-\underset{\begin{smallmatrix}  || \\  O \end{smallmatrix}}{\mathop{C}}\,=C{{D}_{3}}\]

    C) \[{{H}_{2}}C=\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}D\]

    D) \[{{H}_{2}}C=\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{C}}\,=CH{{D}_{2}}\]

    E) \[{{D}_{2}}C=\underset{\begin{smallmatrix}  | \\  OD \end{smallmatrix}}{\mathop{C}}\,-C{{D}_{3}}\]

    Correct Answer: A

    Solution :

    \[\underset{enol\text{ }form\text{ }of\text{ }acetone}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}}}\,+{{D}_{2}}O\xrightarrow[{}]{{}}\] \[{{H}_{3}}C-\underset{\begin{smallmatrix}  | \\  OD \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}\]


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