| 1. A metal M for which\[E{}^\circ \]for the half reaction \[{{M}^{n+}}+n{{e}^{-}}=M,\]is very negative will be a good reducing agent |
| 2. The oxidizing power of the halogens decreases from chlorine to iodine |
| 3. The reducing power of hydrogen halides increases from hydrogen chloride to hydrogen iodide. |
A) 1, 2 and 3
B) 1 and 2
C) 1 only
D) 2 and 3 only
E) 3 only
Correct Answer: A
Solution :
| I. \[Reducing\text{ }character\propto \frac{1}{reduction\text{ }potentials}\] |
| II. Oxidising power of halogens decreases from\[{{F}_{2}}\]to\[{{I}_{2}}\]because their reduction potentials decreases from fluorine to iodine. |
| III. The reducing power of hydrogen halides increases from hydrogen chloride to hydrogen iodide since, the stability of the\[HX\]bond decreases in the same order. Hence, all statements are correct. |
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