CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    The successive ionization energy values for an element X are given below:
    (i) 1st ionization energy \[=410\text{ }kJ\text{ }mo{{l}^{-1}}\]
    (ii) 2nd ionization energy\[=820\text{ }kJ\text{ }mo{{l}^{-1}}\]
    (iii) 3rd ionization energy\[=1100\text{ }kJ\text{ }mo{{l}^{-1}}\]
    (iv) 4th ionization energy\[=1500\text{ }kJ\text{ }mo{{l}^{-1}}\]
    (v) 5th ionization energy\[=3200\text{ }kJ\text{ }mo{{l}^{-1}}\]
    Find out the number of valence electron for the atom

    A) 4                                             

    B) 3

    C) 5                             

    D)        2

    E) 1

    Correct Answer: A

    Solution :

    The ionization energy values for valence electrons are comparable to remove electrons from inner shell very high amount of energy is needed. In the given values there is a biggest jump between\[I{{E}_{4}}\]and\[I{{E}_{5}}\]. Hence, there are four valence electrons for the atom\[X\].


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