CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    On a humid day in summer, the mole fraction of gaseous\[{{H}_{2}}O\](water vapour) in the air at \[25{}^\circ C\]can be as high as 0.0287. Assuming a total pressure of 0.977 atm. What is the partial pressure of dry air?

    A) 94.9 atm              

    B) 0.949 atm

    C) 949 atm               

    D)        0.648 atm

    E) 1.248 atm

    Correct Answer: B

    Solution :

    \[{{P}_{{{H}_{2}}O}}={{X}_{{{H}_{2}}O}}{{P}_{total}}\] \[=0.0287\times 0.977\] \[=0.028\text{ }atm\]                 \[{{P}_{total}}={{P}_{dry\,air}}+{{P}_{{{H}_{2}}O}}\]                 \[{{P}_{dry\,air}}={{P}_{total}}-{{P}_{{{H}_{2}}O}}\] \[=0.977-0.028=0.949\text{ }atm\]


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