2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    5.6 g of an organic compound on burning with excess of oxygen gave 17.6 g of\[C{{O}_{2}}\]and 7.2 g of\[{{H}_{2}}O\]. The organic compound is:

    A) \[{{C}_{6}}{{H}_{6}}\]                    

    B)        \[{{C}_{4}}{{H}_{8}}\]

    C) \[{{C}_{3}}{{H}_{8}}\]                    

    D)        \[C{{H}_{3}}COOH\]

    E) \[C{{H}_{3}}CHO\]

    Correct Answer: B

    Solution :

    \[Organic\text{ }compound\xrightarrow{[O]}\underset{17.6\,g}{\mathop{C{{O}_{2}}}}\,+\underset{7.2g}{\mathop{{{H}_{2}}O}}\,\] % of \[C=\frac{12}{44}\times \frac{17.6}{5.6}\times 100=85.7%\] % of \[H=\frac{2}{18}\times \frac{7.2}{5.6}\times 100=14.28%\]
    Element Percentage Relative no. of atoms Simplest ration
    C 85.7 85.7/12=7.14 7.14/7.14=1
    H 14.28 14.28/1 =1428 14.28/7.14 =2
    Hence, empirical formula of compound\[=C{{H}_{2}}\] \[\therefore \]molecular formula of compound \[={{C}_{4}}{{H}_{8}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner