A) 6
B) 1
C) 7
D) 2
E) 3
Correct Answer: E
Solution :
\[C{{r}_{2}}O_{7}^{2-}+14{{H}^{+}}+6{{e}^{-}}\xrightarrow[{}]{{}}2C{{r}^{3+}}+7{{H}_{2}}O\] \[\begin{align} & \underline{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2{{I}^{-}}\xrightarrow{{}}{{I}_{2}}+2{{e}^{-}})\times 3} \\ & C{{r}_{2}}O_{7}^{2-}+14{{H}^{+}}+6{{I}^{-}}\xrightarrow{{}} \\ \end{align}\] \[2C{{r}^{3+}}+7{{H}_{2}}O+3{{I}_{2}}\] Hence, number of moles of\[{{I}_{2}}\]produced = 3
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